ЯсноПонятно24

To simplify this expression, we can first rewrite the biconditional (↔) as an implication (→) in both directions:

P → ((Q → ¬P) ∧ (¬P → Q))

Next, we can simplify the expression by distributing the P → operator:

(¬P ∨ ((Q → ¬P) ∧ (¬P → Q)))

Now, we can simplify the expression further by expanding the implications:

(¬P ∨ ((¬Q ∨ ¬P) ∧ (P ∨ Q)))

Now, we can simplify the expression by distributing the ¬P operator:

(¬P ∨ (¬Q ∨ ¬P) ∧ (¬P ∨ P ∨ Q))

Now, we can simplify the expression further by using the law of excluded middle (P ∨ ¬P = True) and the law of non-contradiction (P ∧ ¬P = False):

(¬Q ∨ True) ∧ True

Finally, we simplify the expression to get the final result:

True ∧ True

Therefore, the simplified expression is True.